Question

what is the value of the expression-x(y-8)^2

Answer 1

\[x(y-8)^2\]


\[x(y-8)(y-8)\]


\[x(y^2-16y+64)\]


\[xy^2-16xy+64x\]


So \[x(y-8)^2=xy^2-16xy+64x\]

Answer 2

oops i forgot if the value of x is -2 and the value of y is 5

Answer 3

\[x(y-8)^2\]


\[(-2)(5-8)^2\]


\[(-2)(-3)^2\]


\[(-2)(9)\]


\[-18\]


So \[x(y-8)^2=-18\] when x=-2 and y=5

Answer 4

thanks