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Whats the equation of the line passing through the point (3, -2) and parallel to y = 3x - 6.
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slope is 3 so use \[y+2=3(x-3)\] as a start
parallel=same slope y=mx+b , m=3 , (3,-2) -2=3(3)+b -2=9+b -9-2=b -11=b y=3x-11
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