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OpenStudy (anonymous):
If a matrix has repeated eigenvalues of 0, can its eigenspace matrix still be independent? Although it is usually said that the eigenspace cannot be independent if there are repeated eigenvalues, in a case if there is say 2 eigenvalues that are 0, this means that the dim(N(A))=2 and so isn't it possible that each of the eigenvalue of zero can still have its own independent eigenvector?
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