Mathematics
24 Online
OpenStudy (anonymous):
Got a 70% on a quiz so I want to understand what I got wrong. Click on this question to read the answers what i got wrong.
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OpenStudy (anonymous):
Evaluate 2a^3 + (2a)^2
I got 24?
OpenStudy (anonymous):
a = ?
OpenStudy (anonymous):
a=2 sorry
OpenStudy (anonymous):
2^3*2 +4*2^2 = 32
OpenStudy (anonymous):
2(a)^2+4(a^2)
2(2)^2+4(2^2)
8+16=24
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OpenStudy (anonymous):
you got 24 wrong
OpenStudy (anonymous):
hahd 2a^3 not 2a^2
myininaya (myininaya):
=32 not 24
OpenStudy (anonymous):
oh my bad blurry computer screen still havent installed software
OpenStudy (anonymous):
Solve for t in the equation B = 9s^2t.
a. t=9s^2-B
b. t=B-9s^2
c. t=9s^2/B
d. t=B/9s^2
I got B?
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myininaya (myininaya):
d
OpenStudy (anonymous):
Oh wow I did it 2a^2 not 2a^3
OpenStudy (anonymous):
\[2a^3 + (2a)^2\]
\[2\times 2^3+(2\times2)^2\]
\[2\times 8+4^2\]
\[16+16\]
\[32\]
OpenStudy (anonymous):
Solve for c in the equation a=b-c/c
OpenStudy (anonymous):
c=-b/a+1
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OpenStudy (anonymous):
c=b/a+1
OpenStudy (anonymous):
c=a+1/b
OpenStudy (anonymous):
hehe stupid mistakes live with them i make the all the time, and face palm myself alot
OpenStudy (anonymous):
c=-a+1/b
OpenStudy (anonymous):
\[a=\frac{b-c}{c}\]
\[ca=b-c\]
\[ca+c=b\]
\[c(a+1)=b\]
\[c=\frac{b}{a+1}\]
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OpenStudy (anonymous):
c =a+1
---
b
OpenStudy (anonymous):
there seems to be a difference of opinion here. did i write the problem correctly?
OpenStudy (anonymous):
satellite's right
sorry got confused with numerator and denominator sorry