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The perimeter of a rectangle is 52. The length is 6 greater than the width. Find the length and width of this rectangle.
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someeone answer it
answer it Mybrainvsme
working on it.
I wish i had paper
ok got it hold on
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:D w = 10 and L = 16. 10 + 10 +16 +16 = 52
L = w+ 6 so plug this into 2w+2l = 52 2w+2(w+6) = 52 2w+2w+12 = 52 2w+2w = 40 4w=40 w = 10 l = 10 + 6 l = 16
sure lol 2(x+6)+2y=52 simplify
math don't you take my glory.
i'm fluttering hungry.
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