Question

Find the vertex and the axis of symmetry for the parabola with the given equation.
y=5x^2-30x+47

Answer 1

vertex: (3,2)
symmetry x=3

Answer 2

Use
x = -b/2a

Answer 3

yes do that

Answer 4

Right

Answer 5

x=-b/(2a) for axis of symmetry
ax^2+bx+c
b=-30
a=5
x=-(-30)/(2*5)=30/10=3
solve for y
5x^2-30x+47
5(3)^2-30(3)+47
5*9+47-90
45+47-90
92-90
y=2