Question

c-1/8 *4/1-c^2?

Answer 1

breeezy try using equation editor

Answer 2

this \[\frac{c-1}{8}\cdot\frac{4}{1-c^2}\]

?

Answer 3

-c^2+c-1/2

Answer 4

a parabola with 2 complex roots

Answer 5

1/2 - i/2 and
1/2+i/2

Answer 6

\[\frac{c-1}{8}*\frac{4}{1-c^2}\]
\[\frac{c-1}{8}*\frac{4}{-1(c^2-1)}\]
\[\frac{c-1}{8}*\frac{4}{-1(c+1)(c-1)}\]
Cancel:
\[\frac{1}{2}*\frac{1}{-1(c+1)}\]
\[\frac{1}{-2c-2}\]

Answer 7

There's no equals sign so you can only simplify. I'm not sure the parabola is what they're aiming for but without feedback there's no way to be sure.

Answer 8

\[c-1/2-c ^{2}\]\[(-1/2)(c ^{2}-2c+1)=(c-1)^{2}/(-2)\]
i hope it is right