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If f(x) = loge x and x >0, prove that f( u v w) = f(u) + f(v) + f(w).
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log base (e)?
so ln(x)
ya log base e
f(u*v*w)=ln(u*v*w)=ln(u)+ln(v)+ln(w)
rules of log
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what is ln??
f[u*v*w]=log(u*v*w)=log(u)+log(v)+log(w) = f[u]+f[v]+f[w]
\[\ln(x)=\log_e(x)\]
and f(u)=ln(u) f(v)=ln(v) f(w)=ln(w) f(u)+f(v)+f(w)=ln(u)+ln(v)+ln(w)
and as zarkon wrote ln means natural log or a log with the base value being e
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is log a +log b = log a *log b???
log(a)+log(b)=log(a*b)
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