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Show that each one of the following is an even function: (i) f(x) = 1/x2 for all x Є R – {0} (ii) f(x)=ІxІ/(x2 + 1) for all x Є R
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show f(-x)=f(x)
even function retain the same value when you negate the x f(-x) = f(x)
how ????
show please
\[f(-x)=\frac{1}{(-x)^2}=\frac{1}{x^2}=f(x)\]
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x = a ; and x = -a; solve for f(a) and f(-a) perhaps
\[f(-x)=\frac{|-x|}{(-x)^2+1}=\cdots\]
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