Question

how to simplify (x^3-8)/x-2

Answer 1

i felt this was ishaan94!!

Answer 2

\[x^3-8=(x-2)(x^2+2x+4)\] then cancel

Answer 3

x^3-8=(x-2)(x^2+2x+4)
so cancel x-2

Answer 4

the top facotrs to (x-2)(x^2+2x+4)
which means the (x-2) terms cancel out.
Leaving only (x^2+2x+4)

Answer 5

difference of two cubes
\[a^3-b^3=(a-b)(a^2+ab+b^2)\]

Answer 6

i mean the (x-2) terms divide out

Answer 7

you get it?

Answer 8

the answer is x^2-6

Answer 9

no

Answer 10

no you can see that answer is x^2+2x+4 as x-2 cancels out

Answer 11

i will write it out
\[\frac{x^3-8}{x-2}=\frac{(x-2)(x^2+2x+4)}{x-2}=x^2+2x+4\]

Answer 12

@shana would you like to try it with numbers and see?