Question

(y-3)(y+6)=(y-5)^2

Answer 1

y = -6,3

Answer 2

and y can't be equal to 5

Answer 3

Expand each side getting:
\[y ^{2}+3y-18=y ^{2}-10y+25\] Subtract y^2 from both sides leaving
3y-18=-10y+25 Add 10y and 18 to both sides of the equation.
13y=43 divide both sides by 13
y=43/13