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(y-3)(y+6)=(y-5)^2
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y = -6,3
and y can't be equal to 5
Expand each side getting: \[y ^{2}+3y-18=y ^{2}-10y+25\] Subtract y^2 from both sides leaving 3y-18=-10y+25 Add 10y and 18 to both sides of the equation. 13y=43 divide both sides by 13 y=43/13
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