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8/c-1+4/c^2-1?
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Is this (8/(c-1+4))/(c^2-1)? If so, you have: 8*(c^2-1)/(c+3) Which should simplify to: 8c^2-8/c+3. I do not have scrap paper on me as I am on a train right now, but I believe this is correct. You use the concept of complex fractions and inverses. http://www.tutorsean.net
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