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Mathematics 19 Online
OpenStudy (anonymous):

In a recent years,it was estimate that 55% of US .adult Internet users had access to high-speed Internet connection at home or on the job.What is the probability that exactly 2 out of 5 randomly selected U.S. adults had access to high-speed Internet connections?

OpenStudy (zarkon):

binomial distribution

OpenStudy (anonymous):

yes

OpenStudy (zarkon):

\[P(X=x)={n\choose x}p^x(1-p)^{n-x}\]

OpenStudy (anonymous):

40.69%

OpenStudy (anonymous):

i think, its been a while since stats, I don't know if I entered it in the calculator right, sounds about right though

OpenStudy (zarkon):

0.275653125

OpenStudy (anonymous):

just did it again, zarkon is right

OpenStudy (anonymous):

p=55/100?

OpenStudy (zarkon):

yes

OpenStudy (anonymous):

i had it cumulative.

OpenStudy (anonymous):

ty,I got it now

OpenStudy (zarkon):

\[P(X=2)={5\choose 2}(.55)^2(1-.55)^{5-2}\]

OpenStudy (zarkon):

good

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