A spinner is divided into 10 equal segments. Each segment is numbered 1-9and one segment is labeled with "Free Spin." Isaiah spins the spinner ten times and never gets an odd number. What is the probability that he will get an odd number on the eleventh try?

Question

A spinner is divided into 10 equal segments. Each segment is numbered  1-9and one segment is labeled with "Free Spin." Isaiah spins the spinner ten times and never gets an odd number. What is the probability that he will get an odd number on the eleventh try?

anonymous · Answer

The odd is 5/10 or 1/2. each spin is independent to the next

directrix · Answer

I agree with the work of @jack at http://tinyurl.com/n6xx9jn ---------- 5 Odd segments 1, 3, 5, 7, 9 5 Non-odd segments 2, 4, 6, 8, Free Spins from the past have no influence on future spins, so the chance is 5/10 = 50%