Question

Evaluate cot(arcsin1/x-1)

Answer 1

for x=?

Answer 2

I have no idea i think it just needs to be simplified..

Answer 3

is this
\[\cot(\arcsin(\frac{1}{x-1}))\]?

Answer 4

if so we can do it so let me know

Answer 5

yes it is

Answer 6

wow you are back?

Answer 7

make a triangle.
"opposite side" label 1
hypotenuse label x-1
find the adjacent side by pythagoras get
\[\sqrt{(x-1)^2-1}=\sqrt{x^2-2x}\]

Answer 8

cotangent is adjacent over opposite so it is just
\[\sqrt{x^2-2x}\]

Answer 9

I know it took me a while but omg thanks!!! yay