ii Need help with complex number will anyone with a brain help me :{
Okay, what is your question?
ok ii really dnt understand any of it
post and you will get many answers i am sure
what abwt the absolute value of 9+2i
ignore the "i" entirely and square no minus signs
lost
ok good because i was wrong anyway it is \[|a+bi|=\sqrt{a^2+b^2}\]
so you have \[|9+2i|\] right?
STill LosT CoMpLeTeLY LoST...!*
yes
ok what is \[9^2\]?
iiTsx Jusx 9+2i ND iiT SaYsx FiiNd ThEe Absolute value
yes i know. that is what we are going to do. you need to square 9 then square 2 then add those numbers together then take the square root of the result
\[9^2=81\] \[2^2=4\] \[81+4=85\]so far so good?
your answer is \[\sqrt{85}\]
iiHave ThT So SiiMpLiiFiiED iiT WuLD B 5\[\sqrt{?}\]13
no it is \[\sqrt{85}\], which is not 13 because \[13^2=169\] not 85
no but ii have to simplify thee square root of 85 rite
i would leave it like that. if you want a decimal you have to use a calculator
no iijusx have 2 simplfied which i did because 13*5 give yhu 85 which 13 cnt b simplified so it wuld 5 timesx the squareroot of 13 iithink
it is true that \[\sqrt{85}=\sqrt{5\times 13}\] but that is not the same as \[5\sqrt{13}\]
iiWasx TrYiiN 2 Do ThT ThTsx Thee AnSwEr iiGoT BT Yhu PeRnOuNse iiT 5 TiiMesx ThEe Squareroot OF 13 jusx DnT KnW Hw 2 Do ThT Squareroot symbol
hw do yhu include thee squareroot symbol
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