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log(1/100).. and how?
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log(10^(-2))= -2log(10)
log(1/100) = log(100)^-1 = log(10)^-2 = -2log(10) = -2
log is usually base 10 so they should cancel out with the 10 inside so final answer should b -2 as nayeaddo put
great thanks guys!
you're welcome
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You can also remember the important rule that log a - log b = log(a/b)
So this is log(1) - log(100) = 0 - 2 = -2
Good point mtbender
tru u can do that. u should have all the rules written down sumwhere as a reference. my teacher made us do that n it helped us to remember them
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