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OpenStudy (anonymous):
sqrt6x-1=sqrt5 can somebody solve this??
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OpenStudy (anonymous):
\[\sqrt{6x-1}=\sqrt{5}\]
OpenStudy (anonymous):
\[\sqrt{6x-1}=\sqrt{5}\]
OpenStudy (anonymous):
\[\sqrt{6x-1}^{2} = \sqrt{5}^{2}\] 6x-1 =5 6x=6 x=1
hero (hero):
first step, square both sides
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