Question

dia was a famous greek mathematician who lived and worked in alexandria egypt. He was a boy for 1/6 of his life. after 1/12 more, he acquired a beard. After 1/7 he married,in the fifth year of marriage his son was born. the son lived half as many years as dia . dia died four years after his son. how old was dia when he died?

Answer 1

Hell of a question.

Answer 2

yes it is lol

Answer 3

If i remember correctly, this was actually put on the tombstone of a mathematician :)

Answer 4

ask dia when she died

Answer 5

OMG!!! what a question!
my pen's hot trying it

Answer 6

i know im still working it

Answer 7

good to know its a challenge for others as well

Answer 8

wait man i am working

Answer 9

Final age = child + youth + bach + marriage + son's age + 4
x =1/6 x +1/12 x +1/7 x + 5 + 1/2x + 4
x=75/84 x +9
x=84

Answer 10

Oh damn.

Answer 11

COULD IT BE?

Answer 12

um i didnt get that lalaly

Answer 13

yeah one problem

Answer 14

Let d be age of dia, s be age of dia's son
d = 2s
son was born in 5th year of marriage which is 1/6+1/7+1/12 = 99/252 = into dia life
son dies 4 years before dia
s = (d-4) - (99/252d +5)
s = 29/42d -9
By substitution
d/2 = 153/252d - 9
d = 306/252d - 18
54/252d = 18
d = 84

Answer 15

i like your way better lalaly

Answer 16

Thankyouuuu xD

Answer 17

Yeah. Lana's is elegant. Just 1 variable.

Answer 18

alright now i got that answer left off the 5thyear

Answer 19

Hmm?

Answer 20

lol i meant :D hehe