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OpenStudy (anonymous):
Find the radius of convergence and interval of convergence of the series x^n / sqrt(n)
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OpenStudy (anonymous):
Never mind I found out the answer. By using the ratio test I get x*(n)^1/2 / (n+1)^1/2 then I took the limit of that and found out that abs(x) < 1 so that's the radius and interval is [-1,1)
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