Essay. According to the U. S. Census Bureau, the total 2008 U.S. population was 303,824,640. The chart below summarizes the 2008 population for five U.S. States.

U. S. State 2008 Population
Missouri 5,911,605
Pennsylvania 12,448,279
Tennessee 6,214,888
Utah 2,736,424
Washington 6,549,224

SOURCE: U. S. Census Bureau

What is the probability that a randomly selected U.S. resident did not live in Missouri? Show step by step work. Round solution to the nearest thousandth.

please show work!

Question

Essay. According to the U. S. Census Bureau, the total 2008 U.S. population was 303,824,640. The chart below summarizes the 2008 population for five U.S. States.

U. S. State 2008 Population 
Missouri 5,911,605 
Pennsylvania 12,448,279 
Tennessee 6,214,888 
Utah 2,736,424 
Washington 6,549,224

SOURCE: U. S. Census Bureau

What is the probability that a randomly selected U.S. resident did not live in Missouri? Show step by step work. Round solution to the nearest thousandth.

please show work!

anonymous · Answer

Take the probability that the resident did live in Missouri, then subtract that value from 1.

Hence,$$1 - 5911605/303824640$$

Use your calculator.

anonymous · Answer

P=5,911,605/ 303,824,640=
0.019

hero · Answer

Good luck with that, lol

anonymous · Answer

still trying to figure this out !

anonymous · Answer

do what isthmus said

lalaly · Answer

Just subtract 5,911,605 from 303,824,640 and you get 297913035  . This number is equivalent to the number of residents that do not live in missourri
297913035  over 303,824,640 is 297913035 /303,824,640. This figure is the probability that a randomly selected U.S. resident did not live in missouri. The rough percentage probability is 98.05%. The decimal equivalent to the nearest thousandth is .981