Question

find the value of x
(i will attach a picture in a second)

Answer 1

solve for x?
\[6x^2+6x=180\]
\[x^2+x=30\]
\[x^2+x-30=0\] quadratic formula

Answer 2

or
\[6x^2+6x=4x^2+8x+40\]
\[2x^2-2x-40=0\]
\[x^2-x-20=0\] hmm two different equations. i doubt they have the same solution

Answer 3

lets see
\[x^2-x-20=0\]
\[(x-5)(x+4)=0\]
\[x=5\] (we can ignore the negative answer

Answer 4

\[x^2+x-30=0\]
\[(x-5)(x+6)=0\]
\[x=5\] ok i guess x = 5