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7^(-3x)=9^(-x-9)
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x~~5.43
i need the answer in base-10 logarithms
\[\ln(7^{-3x})=\ln(9^{-x-9})\] \[-3x \ln(7)=(-x-9)\ln(9)\] \[-3x \ln(7)=-x \ln(9) -9 \ln(9)\] \[9 \ln(9)=3x \ln(7)-x \ln(9)\]
\[9 \ln(9)=x(3 \ln(7)-\ln(9))\]
\[\frac{9 \ln(9)}{3 \ln(7)-\ln(9)}=x\]
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