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Solve the equation for x: 14x2 - 28x = 0 {-14, 28} {2, -7} {0, 2} no solution
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C for Cat.
zero is pretty clearly one solution because each term has an x in it
{0, 2}
if you want to now if 2 works, check by replacing x by 2 you get \[14\times 2^2-28\times 2=56-56=0\]
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