Joe has a collection of nickels and dimes that is worth $6.10. If the number of dimes was tripled and the number of nickels was decreased by 49, the value of the coins would be $14.05. How many nickels and dimes does he have?
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Question

anonymous · Answer

let x be the number of dimes and y be the nickles
x+y=6.10
3x+y-49=14.02

anonymous · Answer

solve it to get the answer

anonymous · Answer

solve it for me

saifoo.khan · Answer

lol, hashir.. solve.

anonymous · Answer

awwwwww!!!!!!!!!!!!!!!11

anonymous · Answer

>.> well show them how to solve it XD

saifoo.khan · Answer

hashir baita, aap kuch bhool rahay hain

anonymous · Answer

x+y=6.10
3x+y-49=14.05

anonymous · Answer

solve it urself honey girl!!!!!!!

anonymous · Answer

yaad a gaya

saifoo.khan · Answer

baar baar na bhola karo!

anonymous · Answer

i cannot get the second equation

anonymous · Answer

3x=dimes tripled
y-49=reduced by 49

anonymous · Answer

then?

anonymous · Answer

:P for the first equation subtract x or y, I'll solve for  x since it's easier IMO. x = 6.10-y

now plug in your new x into the second equation 3(6.10-y)+y-49 = 14.02 

can you solve from here?

anonymous · Answer

no

anonymous · Answer

why not D:

anonymous · Answer

tell me what you think you should do now

anonymous · Answer

well you have to distribute 3. which means multiply 3 by everything in the ( )
so 3x6.10 and 3x-y 
so you get 
18.30-3y+y-49=14.02

anonymous · Answer

do you know how to combine like terms?