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solve for x. logx + log(x-3)=1
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you can rewrite it as log of product
The sum of logs is the log of the product. \[log(a) + log(b) = log(a\cdot b)\]
So you can use that to re-write your equation as: \[log(x(x-3)) = 1\]
Now try raising 10 to the power of both sides.
great thanks a ton
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