Question

one angle of a triangle is twice as large as another. the measure of the third angle is 30 degrees greater than the measure of the smallest angle. find the measure of each angle. (180 degrees).

Answer 1

lets solve it by equations
let the measure of first angle be x
therefore 2nd angle is 2x
third is 30 more than smallest therefore third is 30+x
add them
x+2x+x+30=180
4x=150
x=150/4

Answer 2

get it?