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Graph the function by hand. Find the vertex; round approx coodinates to the second decimal place. 3x^2-y+5=6x
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Let's get it into y=_____ forms 3x^2-6x+5=y
vertex equation -b ---- 2a
Wasn't correct according to the computer, but thanks anyway.
I am not there yet
6 ---- = -1/2 -12
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ok
plug in -1/2 into function
(-1/2,35/4)
ax^2+bx+c=y : general equation 3x^2-6x+5=y : ur equation for vertex x=-b/(2a) for ur equation a=3 b=-6 c=5 is what imranmeah did
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