Question

find the range of f.
f(x)= sin(arctanx).

Answer 1

arctan(x)'s range is from:
\[\left(-\frac{\pi}{2},\frac{\pi}{2}\right)\]
so sin(arctan(x)) should be from:
\[(-1,1)\]
i believe.

Answer 2

wouldn't it just be -1 to 1 ??