If a pro basketball player has a vertical leap of about 20 inches, what is his hang time? Use the hang time function V=48 T^2.
(Simply your answer. Type and integer or a decimal. Round to the nearest tenth.)

Question

anonymous · Answer

wouldn't it just be 20=48t²?

anonymous · Answer

$$T = \sqrt{V/48}$$

But what's the units of that equation?... i know nothing about you imperial people and your equations :-P

Assuming that equation takes V (=vertial leap) in inches,
T = 0.6455 (seconds??) ... that doesn't sound long enough.

anonymous · Answer

Rounding to the nearest tenth... T = 0.6 (secs?)

dumbcow · Answer

yeah thats right
now 20 inches is only like a foot and a half so yeah you are not in the air as long as you prob think you are