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i hate factoring can someone lend a hand?? 2y^2-32=0
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y=4.-4will be better....
u just have to factor right?
yes but i dont understand what you did dont i need (x plus/minus blank) times (x plus/minus blank)??
everytime they arent that way.
so what was the answer?
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2(y^2-16) = 0 2(y-4)(y+4)=0 <---answer.
can i put the 2 back in if i need to find the solution?
2y^2-32=0 2(y^2-16)=0 (y^2-4^2)=0 (y-4)(y+4)=0
yes u can, but its better to write.
k cool thanks for the help
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