is there anyone can help in solving bollean algebra problem ------ - - x=a.b+c+a.c+b here there is a whole bar on a.b+c and also a bar on c.there is another bar +a.c where c have also bar
a bar indicates a negation; negate first, multiply second, and add last
Okay, I tried to work this out a few times the other day and made a few mistakes so didn't post it, but here goes again. \[\overline{AB+\overline C}+A\overline C +B\]\[(\overline A+\overline B)C+A\overline C +B\]\[\overline AC + \overline BC+A\overline C+B\]\[\overline AC + \overline BC+A\overline C + B(C+\overline C)\]\[\overline AC + \overline BC+A\overline C + BC +B\overline C \]\[\overline AC +A\overline C + C + B \overline C\]\[C + \overline C(A+B)\] thats about as far as I could get it.
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