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125-t^6 ------------- factor it
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\[x^3-y^3=(x-y)(x^2+xy+y^2)\]
so wuts the answer??
\[125=(5)^3\] \[t^6=(t^2)^3\]
so \[(5)^3-(t^2)^3=?\]
oh ok thnxs
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welcome :)
but wait thats not factored
+u need to substitute into the identity that math gave in his first post
x=5 and y = t^2
so it would b ( 5-t^2) ( t^4+5t^2+t^4)
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gj :)
kk and i got another question
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