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Mathematics 16 Online
OpenStudy (anonymous):

factoring: 4xy² -4xz²

OpenStudy (aroub):

4x(y-z)(y+z)

jimthompson5910 (jim_thompson5910):

\[\large 4xy^2-4xz^2\] \[\large 4x(y^2-z^2)\] \[\large 4x(y-z)(y+z)\] So \[\large 4xy^2-4xz^2=4x(y-z)(y+z)\]

OpenStudy (anonymous):

thank you so much!

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