Question

radicals: √3 * √6

i got 3√2, is this right?

Answer 1

You are correct, \[\sqrt{3}\sqrt{6}=\sqrt{18}=\sqrt{9*2}=\sqrt{9}\sqrt{2}=3\sqrt{2}\]
So \[\sqrt{3}\sqrt{6}=3\sqrt{2}\]

Answer 2

thank youuuu!