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-6+√x-5=-2 i moved -6 over to the other side so now it looks like: √x-5=4 now what?
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square on both sides
*squaring
so the square cancels out the check mark thing that i cant remember the name of?
square root
\[(\sqrt{x-5})^2=(4)^2\]
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\[\large -6+\sqrt{x-5}=-2\] \[\large \sqrt{x-5}=-2+6\] \[\large \sqrt{x-5}=4\] \[\large x-5=4^2\] \[\large x-5=16\] \[\large x=16+5\] \[\large x=21\]
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