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Mathematics 14 Online
OpenStudy (anonymous):

12x^2=3x for x

jimthompson5910 (jim_thompson5910):

12x^2=3x 12x^2-3x=0 3x(4x-1)=0 3x=0 or 4x-1=0 x=0/3 or 4x=1 x=0 or x=1/4 So the solutions are \[\large x=0 \ \ \textrm{or} \ \ x=\frac{1}{4}\]

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