Question

(2x2−18)÷(18−6x)

what is the numerator?

Answer 1

***(2x^2 - 18)

Answer 2

\[\large \frac{2x^2-18}{18-6x}\]



\[\large \frac{2(x^2-9)}{-6(x-3)}\]



\[\large \frac{2(x-3)(x+3)}{-6(x-3)}\]



\[\large \frac{2(x+3)}{-6}\]



\[\large -\frac{x+3}{3}\]
So \[\large \frac{2x^2-18}{18-6x}=-\frac{x+3}{3}\]

Answer 3

2(x^2-9)/6(x-3)
2(x-3)(x+3)/6(x-3)
x+3/3(x-3)

the numerator is x+3