Question

help!
the problem is:

write a quadratic function in standard form with zeros 6 and -8

(the answer is f(x)=x^2+2x-48)

Answer 1

x=6 or x=-8

x-6=0 or x+8=0

(x-6)(x+8)=0

x^2+8x-6x-48=0

x^2+2x-48=0

So the function f(x)=x^2+2x-48 has the zeros 6 and -8