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x^2-2x-15 less than or equal to 0
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\[x^2-5x+3x-15 \le 0\]\[x(x-5)-3(x-5) \le 0\]
(x-5)(x-3) le 0
\[x ^{2}-2x-15=(x-5)(x+3)\le0\]
Only when the graphs falls in this interval: \[-3\le x \le 5\]
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