Question

im confused on what to do:

for h(x)=2x^2+6x-9 and k(x)= 3x^2-8x+8, find h(x)- 2k(x)

(the answer is -4x^2+22x-25 )

Answer 1

\[\large k(x)= 3x^2-8x+8\]

\[\large 2k(x)=2(3x^2-8x+8)\]

\[\large 2k(x)=6x^2-16x+16\]

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\[\large h(x)-2k(x)\]

\[\large (2x^2+6x-9)-(6x^2-16x+16)\]

\[\large 2x^2+6x-9-6x^2+16x-16\]

\[\large -4x^2+22x-25\]

So \[\large h(x)-2k(x)=-4x^2+22x-25\]