Question

What are the x– and y–intercepts of y = 2x2 – 10x + 8? solving quadratics by completing the square

Answer 1

plug x=0 for y int
plug y=0 for x int

Answer 2

i dont get it?

Answer 3

x-intercepts


y = 2x^2 – 10x + 8

0 = 2x^2 – 10x + 8

0 = 2(x^2 – 5x + 4)

0 = 2(x-1)(x-4)

x-1=0 or x-4=0

x=1 or x=4

x-intercepts are (1,0) and (4,0)

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y-intercept

y = 2x^2 – 10x + 8

y = 2(0)^2 – 10(0) + 8

y = 8

y-intercept is (0,8)