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Solve. (x – 6)2 = 2 x = 8 ± sqrt2 x = 6 ± sqrt2 x = 3 ± 2 sqrt2 x = 8 ± 2 sqrt2
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\[x^2-12x+36=2\] \[x^2-12x+34=0\] now use quadratic formula \[(-b \pm \sqrt{b^2-4ac})/2a\] where a=1,b=-12 and c=34
final answer is x = 6 ± sqrt2
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