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A riding lawnmower can drive up a 27º incline. In order for a ramp designed to reach a truck bed that is 3 feet above the ground to have a 27º incline, how long should the ramp be? a. 3.37 ft b. 5.89 ft c. 6.61 ft d. 9 ft
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draw a triangle
sin ( 3 / x) = 27 x= hypotneuse
answer c. 6.61
\[\text{rampLength} =3\text{ }\text{Csc}[27{}^{\circ}]=6.61 \text{feet} \]
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