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Use this triangle to calculate the specified trigonometric values. Calculate sin
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x/12
x/12 = degree
lorda mercy
\[\cos(\theta)=\frac{10}{12}=\frac{5}{6}\]
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\[\theta=\cos^{-1}(\frac{5}{6})\]
now use a caclulator
and how do you get tan?
you need the third side. use pythagoras
oh you just need sine? third side is \[\sqrt{12^2-10^2}\]
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which is \[\sqrt{44}=2\sqrt{11}\]
for sin or tan?
so \[\sin(\theta)=\frac{2\sqrt{11}}{12}=\frac{\sqrt{11}}{6}\]
and \[\tan(\theta)=\frac{\sqrt{11}}{5}\]
\[\text{Sin}\left[\text{ArcCos}\left[\frac{10}{12}\right]\right]=\frac{\sqrt{11}}{6}=0.552771 \]
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