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Mathematics 23 Online
OpenStudy (safia21):

Use this triangle to calculate the specified trigonometric values. Calculate sin

OpenStudy (safia21):

OpenStudy (curry):

x/12

OpenStudy (curry):

x/12 = degree

OpenStudy (anonymous):

lorda mercy

OpenStudy (anonymous):

\[\cos(\theta)=\frac{10}{12}=\frac{5}{6}\]

OpenStudy (anonymous):

\[\theta=\cos^{-1}(\frac{5}{6})\]

OpenStudy (anonymous):

now use a caclulator

OpenStudy (safia21):

and how do you get tan?

OpenStudy (anonymous):

you need the third side. use pythagoras

OpenStudy (anonymous):

oh you just need sine? third side is \[\sqrt{12^2-10^2}\]

OpenStudy (anonymous):

which is \[\sqrt{44}=2\sqrt{11}\]

OpenStudy (safia21):

for sin or tan?

OpenStudy (anonymous):

so \[\sin(\theta)=\frac{2\sqrt{11}}{12}=\frac{\sqrt{11}}{6}\]

OpenStudy (anonymous):

and \[\tan(\theta)=\frac{\sqrt{11}}{5}\]

OpenStudy (anonymous):

\[\text{Sin}\left[\text{ArcCos}\left[\frac{10}{12}\right]\right]=\frac{\sqrt{11}}{6}=0.552771 \]

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