Question

3√x-2-8=8 (I'm trying to solve for x, but I'm not sure if I'm doing this correctly.)

Answer 1

( by the way its square root of x-2.. I'm not sure if it shows that clearly.)

Answer 2

\[\large 3\sqrt{x-2}-8=8\]



\[\large 3\sqrt{x-2}=8+8\]



\[\large 3\sqrt{x-2}=16\]



\[\large \sqrt{x-2}=\frac{16}{3}\]



\[\large x-2=(\frac{16}{3})^2\]



\[\large x-2=\frac{256}{9}\]



\[\large x=\frac{256}{9}+2\]



\[\large x=\frac{274}{9}\]

Answer 3

Thank you! Now that I'm looking at this, I feel silly this is easy -_-