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So in this question, Im not sure what i did wrong, for the answer I basically got the original equation written in slope intercept form. (Unless that is the correct answer? ) Write the equation of the line parallel to line 2x-3y=7 and containing the point (5,1).... Did i forget something?
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2x-3y=C 2(5)-3(1)=C 10-3=C 7 = C C = 7 So the equation parallel to 2x-3y=7 and that goes through (5,1) is 2x-3y=7. Make sure that there are no typos or other posting errors.
Nope no typos, I wonder if this was some sort of trick question, but yeah i got the same response.
Yeah it's either a trick question or there's a typo.
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