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CHECK:Determine if the improper integral diverges or converges. Evaluate if Convergent.
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\[\int\limits_{2}^{\infty}dx/x^3\]
i did it quick so i might have a small error somewhr but i got converges , 1/8
i havent taken calculus yet so i dont know sorry
Correction: http://www.wolframalpha.com/input/?i=integral%282%2Cinf%291%2F%28x^3%29
that is 1/x^3 not x^3
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you were right - it does converge to 1/8
you can see that it is obviously going somewhere unlike x^3... thats obviously ging to infinity but i'll give ya a medal hah
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