Question

6x^2+13x-20=0
solve this as a quadratic equation

Answer 1

\[-b \pm \sqrt{b^2 - 4ac} \over 2a\]

\[-13 \pm \sqrt{13^2 - 4*6*-20} \over 2*6\]

x = \[-13 \pm \sqrt{649} \over 12\]

Answer 2

use the quadratic formula
x = 1.0396 , x = -2.39

Answer 3

nice!!!!
thaks for the answer!!!
^_^