Question

differentiation....
if Y=ln(sinX),then show,d^3Y?dX^3=2cosX/sin^3X ??????????

Answer 1

third derivative right?

Answer 2

sorry.....i am gonna write it again

Answer 3

if y=ln(sinx),then show,d^3y/dx^3y=2cosx/sin^3x????

Answer 4

dy/dx = cos(x)/sin(x)= cot(x)

d^2y/dx^2= -csc^2(x)

\[\frac{d^3y}{\text{dx}^3}=2 \text{Cot}(x)\text{Csc}^2(x)\]

\[\frac{2 \cos (x)}{\sin (x) }\frac{1}{\sin ^2(x)}\]

Answer 5

thanks a lotttttttttt

Answer 6

i've got ittttt